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Introduction to Hash Tables

Mechanism

A hash table gets O(1) average lookup by never searching at all: a hash function H(key) computes an array index directly from the key's bits, so insert/search/delete jump straight to a bucket instead of scanning or comparing keys one by one. The table trades the O(log n) comparison-based bound of balanced trees for O(1) expected time by spending memory on a sparsely-filled array and accepting that different keys can collide on the same index — handled by chaining (a linked list/bucket per slot) or open addressing (probe to another slot).

Recognize the pattern

Brute force → optimal

Brute force: keep records in an unsorted array/list; Search(key) scans every element comparing keys → O(n) per lookup, O(1) extra space.

Optimal (hash table): Insert/Search/Delete compute index = H(key) and jump to that bucket → O(1) expected time per operation, O(n) extra space for the bucket array plus chain nodes. The cost moves from CPU time (scanning) to memory (a larger, sparser array) and to occasional rehashing when the array fills up.

Complexity, derived

Let n = number of stored entries, m = number of buckets, load factor α = n/m.

Traced example (toy model)

This is a simplified pedagogical model, not a trace of any real library. Table size m = 5, hash H(key) = key mod 5. Insert keys 12, 7, 17, 3 in order (chaining on collision):

InsertH(key)=key%5Bucket contents after insert
122bucket2: [12]
72bucket2: [12, 7] (collision, chained)
172bucket2: [12, 7, 17] (collision again)
33bucket3: [3]

Search(17): H(17)=2 → jump to bucket2 → walk chain [12, 7, 17] comparing keys → found after 3 comparisons (worst-case within this bucket), instead of scanning all 4 entries in the whole table. Note: this m=5 layout is a hand-traced toy model built to make chaining and collisions visible. A real production hash table (see the java.util.HashMap example below) uses a different table size and hash-spreading strategy, so it will not necessarily produce the same collisions for the same keys.

Pitfalls

When to use / when not

Use a hash table when you need fast key-based lookup/insert/delete and don't care about ordering — frequency counts, caches, deduplication, index lookups. Not when you need sorted iteration or range queries (min/max/floor/ceiling) — use a balanced BST/TreeMap instead, which gives O(log n) for all ops but supports ordered traversal and range queries that a hash table cannot do faster than O(n log n) (sorting first). Also avoid when keys are small dense integers with a known bound — a plain array indexed directly is simpler and guarantees true O(1) worst case with no hashing/collision overhead. And for tiny n (a handful of keys), a plain linear scan can beat the hash table on constant factors.

StructureLookupOrdered iterationRange query
Hash TableO(1) avgNoNo (O(n log n))
TreeMap (balanced BST)O(log n)YesO(log n + k)
Plain array (dense int keys)O(1) worstYes (by key)O(k)

From toy model to real java.util.HashMap

The mod-5 trace above is a simplification for teaching chaining, not how java.util.HashMap actually indexes. In the real JDK implementation: Integer.hashCode() returns the raw int value; HashMap.hash() only XORs in the high 16 bits of the hashCode with the low 16 bits (a spreading step that matters for large or poorly-distributed hashCodes, but is a no-op for small ints); and with the default initial capacity of 16, the bucket index is hash & 15 (a bitmask, not mod 5). Under that real scheme: 12 & 15 = 12, 7 & 15 = 7, 17 & 15 = 1, 3 & 15 = 3 — four different buckets, so none of these four keys actually collide in a default-capacity HashMap. The code below reflects that real behavior; treat the earlier trace purely as a mechanism illustration.

import java.util.*;

class QuickDemo {
    public static void main(String[] args) {
        Map<Integer, String> ht = new HashMap<>();
        ht.put(12, "Book-A");
        ht.put(7, "Book-B");   // default capacity 16: 12&15=12, 7&15=7 -> different buckets, no collision here
        ht.put(17, "Book-C");  // 17&15=1 -> also a distinct bucket
        ht.put(3, "Book-D");   // 3&15=3 -> also distinct

        System.out.println(ht.get(17));   // O(1) expected -> "Book-C"
        ht.remove(7);                      // O(1) expected
        System.out.println(ht.containsKey(7)); // false
    }
}

Takeaways

Recall: Why does doubling-and-rehashing keep insertion at amortized O(1) instead of making it O(n) per insert?


Synthesized from standard hash table theory (CLRS-style analysis of chaining/load factor), the source notes on naive Hash Table implementation (Insert/Search/Delete, modular hashing), and java.util.HashMap's documented default capacity (16) and hash-spreading behavior.

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