1 Basic Sum
Problem Statement
Calculate the Sum of the First N Natural Numbers Using a Recursive Approach.
The sum of first N natural numbers is equal to N + (N-1) + (N-2) + ... + (3) + (2) + (1). The following table shows a sample input/output description table:
| Input (s) | Output (s) | Explanation |
|---|---|---|
| N = 5 | Sum = 15 | The first 5 natural numbers are 1, 2, 3, 4, and 5. The sum of these numbers is 1 + 2 + 3 + 4 + 5 = 15. |
| N = 10 | Sum = 55 | The first 10 natural numbers are 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10. The sum of these numbers is 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55. |
| N = 1 | Sum = 1 | The first natural number is 1. The sum of this number is 1. |
Try it yourself
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🎯 STRICT STANDOUT — Problem cue: Basic Sum
1. Why
Sum 1..N is purest linear recursion: combine '+', shrink N-1, base ≤0 → 0. Teaches stack cost before clever algorithms.
2. Big-O (K11)
T(N)=T(N-1)+Θ(1) → Θ(N) time; space Θ(N) call frames (no TCO)
Closed form N(N+1)/2 is Θ(1) — recursion is pedagogy
Loop: Θ(N) time, Θ(1) space
3. Pattern + when-NOT (K12)
LINEAR RECURSION. When-NOT: production large N → loop/formula (stack overflow + overhead).
4. Edge (K13)
N=5 → 15; N=1 → 1; N=0 → 0; N<0 → 0; huge N → StackOverflow
5. Panel
Q: Why space O(N)? A: Each call waits for child; frames live until unwind.
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