Solution Basic Sum
Problem Statement
Calculate the Sum of the First N Natural Numbers Using a Recursive Approach.
The sum of first N natural numbers is equal to N + (N-1) + (N-2) + ... + (3) + (2) + (1). The following table shows a sample input/output description table:
| Input (s) | Output (s) | Explanation |
|---|---|---|
| N = 5 | Sum = 15 | The first 5 natural numbers are 1, 2, 3, 4, and 5. The sum of these numbers is 1 + 2 + 3 + 4 + 5 = 15. |
| N = 10 | Sum = 55 | The first 10 natural numbers are 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10. The sum of these numbers is 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55. |
| N = 1 | Sum = 1 | The first natural number is 1. The sum of this number is 1. |
Solution
The algorithm to calculate the sum of the first N natural numbers using recursion can be defined as follows:
- If
Nis equal to0or less, return0(base case). - Otherwise, return the sum of number
Nand the recursive call to calculate the sum ofN-1.
The recursive approach works by breaking down the problem into smaller subproblems. We calculate the sum of N by adding N to the sum of the numbers from 1 to N-1. This process continues until the base case is reached, where N is 0 or less.
The base case stops the recursion and returns 0. By summing the numbers in a decreasing order, we ensure that each number is added to the previous sum, eventually giving us the total sum of the first N natural numbers.
Code
Here is the code for this algorithm:
public class Solution {
public static int calculateSum(int N) {
if (N <= 0) {
return 0; // Base case
}
return N + calculateSum(N - 1); // Recursive call
}
public static void main(String[] args) {
// Example inputs
int[] examples = { 5, 10, 1 };
for (int N : examples) {
int sum = calculateSum(N);
System.out.println("Sum of first " + N + " natural numbers: " + sum);
}
}
}
Time and Space Complexity
The time complexity of the algorithm is
The space complexity of the algorithm is also
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