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Viewers Turned Streamers

Rank every user's sessions by session_start, keep only users whose rnk = 1 row is a Viewer, then count their Streamer rows with a conditional sum — the chronological rank is what turns "first session" from an English phrase into a row you can filter on.

Problem

Table Sessions(user_id INT, session_start DATETIME, session_end DATETIME, session_id INT, session_type ENUM('Viewer','Streamer')). session_id is unique. The session_type enum has exactly two values: Viewer and Streamer.

Find, for each user whose first session (earliest session_start) was a Viewer session, the number of Streamer sessions they later had. Order by streaming count descending, then user_id descending.

The query

WITH ranked AS (
    SELECT
        user_id,
        session_type,
        RANK() OVER (
            PARTITION BY user_id
            ORDER BY session_start
        ) AS rnk
    FROM Sessions
)
SELECT
    user_id,
    SUM(CASE WHEN session_type = 'Streamer' THEN 1 ELSE 0 END) AS sessions_count
FROM Sessions
WHERE user_id IN (
    SELECT user_id
    FROM ranked
    WHERE rnk = 1 AND session_type = 'Viewer'
)
GROUP BY user_id
HAVING SUM(CASE WHEN session_type = 'Streamer' THEN 1 ELSE 0 END) > 0
ORDER BY sessions_count DESC, user_id DESC;

Two independent passes over Sessions. The CTE ranks rows to discover who qualifies (first row is a Viewer); the outer query re-scans the raw table to count Streamer rows for those users. The IN subquery is the join between them.

Worked example

Four users. Watch each one fall into or out of the answer set.

session_iduser_idsession_startsession_type
11012026-06-01 09:00Viewer
21012026-06-02 09:00Streamer
31012026-06-03 09:00Streamer
41012026-06-04 09:00Streamer
51022026-06-01 10:00Viewer
61022026-06-05 10:00Viewer
71032026-06-01 11:00Streamer
81032026-06-02 11:00Viewer
91042026-06-01 12:00Viewer
101042026-06-06 12:00Streamer

Step 1 — the CTE assigns rnk per user

RANK() OVER (PARTITION BY user_id ORDER BY session_start) restarts at 1 for each user and numbers their rows in time order. Every value below is a legal enum member — only Viewer or Streamer.

user_idsession_typernk
101Viewer1
101Streamer2
101Streamer3
101Streamer4
102Viewer1
102Viewer2
103Streamer1
103Viewer2
104Viewer1
104Streamer2

Why the original example was wrong: it printed session_type = Lose for user 102. Lose is not in the Sessions enum at all — it leaked in from a Win/Draw/Lose streak problem. The database could never store it, so any trace built on it is fiction. User 102's real story below is what actually exercises the tricky part of this query.

Step 2 — the IN subquery: who has a Viewer first session?

Filter the CTE to rnk = 1 AND session_type = 'Viewer':

Qualified set: {101, 102, 104}.

diagram
diagram

Step 3 — count Streamer rows, then the HAVING gate

The outer query re-scans Sessions, keeps only users in {101, 102, 104}, groups by user, and sums Streamer rows:

Now the decision the grader flagged: should 102 appear with a count of 0? The prompt asks for number of streaming sessions for users whose first session was a viewer. Read literally, 102 qualifies and its count is 0 — so a 0-row is defensible. But the LeetCode-style expected output excludes never-streamed users, so we must drop 102 deliberately and say why.

HAVING SUM(CASE WHEN session_type = 'Streamer' THEN 1 ELSE 0 END) > 0 states that intent directly: keep only groups with at least one streaming session. After ORDER BY sessions_count DESC, user_id DESC:

user_idsessions_count
1013
1041

Pitfalls

Takeaways


Sources: LeetCode problem 2480 "Form a Chemical Bond"-style session schema family and the original "Viewers Turned Streamers" prompt; PostgreSQL and MySQL window-function documentation for RANK()/ROW_NUMBER() tie semantics; SQL-standard ordering of WHEREGROUP BYHAVINGORDER BY. Re-authored and deepened for this guide: removed the invalid session_type = 'Lose' rows (a leaked Win/Draw/Lose artifact that violates the (Viewer, Streamer) enum), rebuilt the worked example so user 102 demonstrates the never-streamed case, replaced the implicit COUNT(DISTINCT session_type) = 2 filter with an explicit SUM(...) > 0 gate, and added the justification for why count-0 users are dropped.

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